Originally created by @stackoverflow on GitHub (Jan 17, 2025).
foo = "foo \#(1)"
The above code renders foo as foo 1 even though this is not syntactically valid Pkl.
In fact any number of # can be used and Pkl will still parse the interpolation.
The correct code would be:
foo = #"foo \#(1)"#
Originally created by @stackoverflow on GitHub (Jan 17, 2025).
```pkl
foo = "foo \#(1)"
```
The above code renders foo as `foo 1` even though this is not syntactically valid Pkl.
In fact any number of `#` can be used and Pkl will still parse the interpolation.
The correct code would be:
```pkl
foo = #"foo \#(1)"#
```
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Originally created by @stackoverflow on GitHub (Jan 17, 2025).
The above code renders foo as
foo 1even though this is not syntactically valid Pkl.In fact any number of
#can be used and Pkl will still parse the interpolation.The correct code would be: