Remove archiver dependency

server/libs/archiver/normalize-path/LICENSE

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+The MIT License (MIT)
+
+Copyright (c) 2014-2018, Jon Schlinkert.
+
+Permission is hereby granted, free of charge, to any person obtaining a copy
+of this software and associated documentation files (the "Software"), to deal
+in the Software without restriction, including without limitation the rights
+to use, copy, modify, merge, publish, distribute, sublicense, and/or sell
+copies of the Software, and to permit persons to whom the Software is
+furnished to do so, subject to the following conditions:
+
+The above copyright notice and this permission notice shall be included in
+all copies or substantial portions of the Software.
+
+THE SOFTWARE IS PROVIDED "AS IS", WITHOUT WARRANTY OF ANY KIND, EXPRESS OR
+IMPLIED, INCLUDING BUT NOT LIMITED TO THE WARRANTIES OF MERCHANTABILITY,
+FITNESS FOR A PARTICULAR PURPOSE AND NONINFRINGEMENT. IN NO EVENT SHALL THE
+AUTHORS OR COPYRIGHT HOLDERS BE LIABLE FOR ANY CLAIM, DAMAGES OR OTHER
+LIABILITY, WHETHER IN AN ACTION OF CONTRACT, TORT OR OTHERWISE, ARISING FROM,
+OUT OF OR IN CONNECTION WITH THE SOFTWARE OR THE USE OR OTHER DEALINGS IN
+THE SOFTWARE.

server/libs/archiver/normalize-path/index.js

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+/*!
+ * normalize-path <https://github.com/jonschlinkert/normalize-path>
+ *
+ * Copyright (c) 2014-2018, Jon Schlinkert.
+ * Released under the MIT License.
+ */
+
+module.exports = function (path, stripTrailing) {
+  if (typeof path !== 'string') {
+    throw new TypeError('expected path to be a string');
+  }
+
+  if (path === '\\' || path === '/') return '/';
+
+  var len = path.length;
+  if (len <= 1) return path;
+
+  // ensure that win32 namespaces has two leading slashes, so that the path is
+  // handled properly by the win32 version of path.parse() after being normalized
+  // https://msdn.microsoft.com/library/windows/desktop/aa365247(v=vs.85).aspx#namespaces
+  var prefix = '';
+  if (len > 4 && path[3] === '\\') {
+    var ch = path[2];
+    if ((ch === '?' || ch === '.') && path.slice(0, 2) === '\\\\') {
+      path = path.slice(2);
+      prefix = '//';
+    }
+  }
+
+  var segs = path.split(/[/\\]+/);
+  if (stripTrailing !== false && segs[segs.length - 1] === '') {
+    segs.pop();
+  }
+  return prefix + segs.join('/');
+};